What is x(1-x)+m(x)-0.1x=0 ?

The solution to x(1-x)+m(x)-0.1x=0 is Parabola with (h,k)=(0.45,-0.2025),p= 1/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x(1-x)+m(x)-0.1x=0

x (1 - x) + m (x) - 0.1 x = 0

(h, k) = (0.45, - 0.2025), p = \frac{1}{4}

Solution steps

x (1 - x) + y - 0.1 x = 0

Rewrite

x (1 - x) + y - 0.1 x = 0

in the standard form

4 \cdot \frac{1}{4} (y - (- 0.2025)) = (x - 0.45)^{2}

Therefore parabola properties are:

(h, k) = (0.45, - 0.2025), p = \frac{1}{4}

y^{2} = - 11 x

x^{2} - x = 4 k (x) + 2

2 y - x^{2} + 24 - 2 x = 0

\frac{( x - ( - 2.93 ) ^{2} )}{4.49} + \frac{y ^{2}}{1.34} = 2

(q) = 2 q^{2} - 40 p + 600

What is x(1-x)+m(x)-0.1x=0 ?
The solution to x(1-x)+m(x)-0.1x=0 is Parabola with (h,k)=(0.45,-0.2025),p= 1/4