Y^2+4X+4Y-4=0

Lösung

Y^{2} + 4 X + 4 Y - 4 = 0

(h, k) = (- 2, 2), p = - 1

Schritte zur Lösung

Y^{2} + 4 X + 4 Y - 4 = 0

Rewrite

Y^{2} + 4 X + 4 Y - 4 = 0

in the standard form

4 (- 1) (X - 2) = (Y - (- 2))^{2}

Therefore parabola properties are:

(h, k) = (- 2, 2), p = - 1

x = (y + 6)^{2} + 5

y = - x^{2} - 6 x - 18

x^{2} + y + 12 x - 10 y = 12

\frac{y}{x} < x - 1

(x - 3)^{2} = 5 (y + 2)