What is x= 1/24 (y+6)^2+2 ?

The solution to x= 1/24 (y+6)^2+2 is Parabola with (h,k)=(2,-6),p=6

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x= 1/24 (y+6)^2+2

x = \frac{1}{24} (y + 6)^{2} + 2

(h, k) = (2, - 6), p = 6

Solution steps

x = \frac{1}{24} (y + 6)^{2} + 2

Rewrite

x = \frac{1}{24} (y + 6)^{2} + 2

in the standard form:

4 \cdot 6 (x - 2) = (y - (- 6))^{2}

Therefore parabola properties are:

(h, k) = (2, - 6), p = 6

(x - 1)^{2} = 4 (y + 1)

3 6^{2} - 64 y^{2} - 504 x + 768 y - 2844 = 0

\frac{1}{2} x = \frac{y - 1}{x + 3}

y \geq 2 x^{2} + 2 x - 3

x, 4 k (x)^{2} + 6 = 5 k (x)^{2} - 4 x + 3

What is x= 1/24 (y+6)^2+2 ?
The solution to x= 1/24 (y+6)^2+2 is Parabola with (h,k)=(2,-6),p=6