What is 4x^2+16y+40x+64y+100=0 ?

The solution to 4x^2+16y+40x+64y+100=0 is Parabola with (h,k)=(-5,0),p=-5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4x^2+16y+40x+64y+100=0

4 x^{2} + 16 y + 40 x + 64 y + 100 = 0

(h, k) = (- 5, 0), p = - 5

Solution steps

4 x^{2} + 16 y + 40 x + 64 y + 100 = 0

Rewrite

4 x^{2} + 16 y + 40 x + 64 y + 100 = 0

in the standard form

4 (- 5) (y - 0) = (x - (- 5))^{2}

Therefore parabola properties are:

(h, k) = (- 5, 0), p = - 5

x^{2} + 8 x + 3 - k (x) = 0

2 a^{2} + 3 a + b = - 2

(y + 1)^{2} = 4 x

16 x^{2} + 56 x + 144 y + 517 = 0

15 x + 3 y = 7 - 5 x + 4 \cdot 9 y^{2}

What is 4x^2+16y+40x+64y+100=0 ?
The solution to 4x^2+16y+40x+64y+100=0 is Parabola with (h,k)=(-5,0),p=-5