What is (y+3/4)^2=2(x+33/32) ?

The solution to (y+3/4)^2=2(x+33/32) is Parabola with (h,k)=(-33/32 ,-3/4),p= 1/2

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(y+3/4)^2=2(x+33/32)

(y + \frac{3}{4})^{2} = 2 (x + \frac{33}{32})

(h, k) = (- \frac{33}{32}, - \frac{3}{4}), p = \frac{1}{2}

Solution steps

(y + \frac{3}{4})^{2} = 2 (x + \frac{33}{32})

Rewrite

(y + \frac{3}{4})^{2} = 2 (x + \frac{33}{32})

in the standard form:

4 \cdot \frac{1}{2} (x - (- \frac{33}{32})) = (y - (- \frac{3}{4}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{33}{32}, - \frac{3}{4}), p = \frac{1}{2}

x = 2 \cdot y - y^{2}

- x^{2} + 11 x + y - 10 < 0

6 (y - 15) = - 2 (x^{2})

3 f (x) - 1 = x^{2} - 1

3 y^{2} + 3 x = 0

What is (y+3/4)^2=2(x+33/32) ?
The solution to (y+3/4)^2=2(x+33/32) is Parabola with (h,k)=(-33/32 ,-3/4),p= 1/2