What is 13^2+4y^2-52x-24y+36=0 ?

The solution to 13^2+4y^2-52x-24y+36=0 is Parabola with (h,k)=(13/4 ,3),p= 13/4

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13^2+4y^2-52x-24y+36=0

1 3^{2} + 4 y^{2} - 52 x - 24 y + 36 = 0

(h, k) = (\frac{13}{4}, 3), p = \frac{13}{4}

Solution steps

1 3^{2} + 4 y^{2} - 52 x - 24 y + 36 = 0

Rewrite

1 3^{2} + 4 y^{2} - 52 x - 24 y + 36 = 0

in the standard form

4 \cdot \frac{13}{4} (x - \frac{13}{4}) = (y - 3)^{2}

Therefore parabola properties are:

(h, k) = (\frac{13}{4}, 3), p = \frac{13}{4}

6 x = 9 y^{2}

f (x) (x)^{- 1} = \frac{1}{3} x - 2

\frac{9 \cdot 1 0 ^{9} \cdot x \cdot x}{y} = 100

x^{2} - 8 x + 64 = 12 y

- 4 = 4 x^{2} + 6 y

What is 13^2+4y^2-52x-24y+36=0 ?
The solution to 13^2+4y^2-52x-24y+36=0 is Parabola with (h,k)=(13/4 ,3),p= 13/4