What is 6x^2+8x^2+12x-32y=178 ?

The solution to 6x^2+8x^2+12x-32y=178 is Parabola with (h,k)=(-3/7 ,-79/14),p= 4/7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

6x^2+8x^2+12x-32y=178

6 x^{2} + 8 x^{2} + 12 x - 32 y = 178

(h, k) = (- \frac{3}{7}, - \frac{79}{14}), p = \frac{4}{7}

Solution steps

6 x^{2} + 8 x^{2} + 12 x - 32 y = 178

Rewrite

6 x^{2} + 8 x^{2} + 12 x - 32 y = 178

in the standard form

4 \cdot \frac{4}{7} (y - (- \frac{79}{14})) = (x - (- \frac{3}{7}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{3}{7}, - \frac{79}{14}), p = \frac{4}{7}

(x + 3)^{2} = - (y + 4)

x^{2} - 12 x + 4 y + 12 = 0

\frac{y ^{2}}{- 40} + 60 = x

x = - \frac{1}{4} (y - 4)^{2} + \frac{1}{2}

x^{2} = 4 (\frac{9}{16}) (y - 2)

What is 6x^2+8x^2+12x-32y=178 ?
The solution to 6x^2+8x^2+12x-32y=178 is Parabola with (h,k)=(-3/7 ,-79/14),p= 4/7