What is ((x-1))/(49)+((y-3)^2)/(36)=1 ?

The solution to ((x-1))/(49)+((y-3)^2)/(36)=1 is Parabola with (h,k)=(50,3),p=-9/49

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((x-1))/(49)+((y-3)^2)/(36)=1

\frac{( x - 1 )}{49} + \frac{( y - 3 ) ^{2}}{36} = 1

(h, k) = (50, 3), p = - \frac{9}{49}

Solution steps

\frac{x - 1}{49} + \frac{( y - 3 ) ^{2}}{36} = 1

Rewrite

\frac{x - 1}{49} + \frac{( y - 3 ) ^{2}}{36} = 1

in the standard form:

4 (- \frac{9}{49}) (x - 50) = (y - 3)^{2}

Therefore parabola properties are:

(h, k) = (50, 3), p = - \frac{9}{49}

(x - 4)^{2} = - 8 (y + 3)

y^{2} = 8 x + 5

y^{2} - 6 y = 8 x - 17

3 x^{2} - 22 x + 42 + 3 y - 10 y = 0

y^{2} = C x + 3

What is ((x-1))/(49)+((y-3)^2)/(36)=1 ?
The solution to ((x-1))/(49)+((y-3)^2)/(36)=1 is Parabola with (h,k)=(50,3),p=-9/49