What is y^2-3x+2y+1=0 ?

The solution to y^2-3x+2y+1=0 is Parabola with (h,k)=(0,-1),p= 3/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^2-3x+2y+1=0

y^{2} - 3 x + 2 y + 1 = 0

(h, k) = (0, - 1), p = \frac{3}{4}

Solution steps

y^{2} - 3 x + 2 y + 1 = 0

Rewrite

y^{2} - 3 x + 2 y + 1 = 0

in the standard form

4 \cdot \frac{3}{4} (x - 0) = (y - (- 1))^{2}

Therefore parabola properties are:

(h, k) = (0, - 1), p = \frac{3}{4}

x^{2} = 2 x - 2 y

\frac{( x - 10 ) ^{2}}{100} - \frac{y + 3 ^{2}}{36} = 1

x, \frac{104}{x} = \frac{500}{0.03 m ( x ) ^{2}}

x^{2} + 2 x + 4 y = 19

(x - 4)^{2} = 4 (- 6) (y - 2)

What is y^2-3x+2y+1=0 ?
The solution to y^2-3x+2y+1=0 is Parabola with (h,k)=(0,-1),p= 3/4