What is 1-(3x^2+5x)/y =0 ?

The solution to 1-(3x^2+5x)/y =0 is Parabola with (h,k)=(-5/6 ,-25/12),p= 1/12

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1-(3x^2+5x)/y =0

1 - \frac{3 x ^{2} + 5 x}{y} = 0

(h, k) = (- \frac{5}{6}, - \frac{25}{12}), p = \frac{1}{12}

Solution steps

1 - \frac{3 x ^{2} + 5 x}{y} = 0

Rewrite

1 - \frac{3 x ^{2} + 5 x}{y} = 0

in the standard form

4 \cdot \frac{1}{12} (y - (- \frac{25}{12})) = (x - (- \frac{5}{6}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{5}{6}, - \frac{25}{12}), p = \frac{1}{12}

y^{2} = - 20 (X - 2)

x = - y^{2} - 1

y^{2} - 2 y + 4 x - 7 = 0

x = - y^{2} + 8

4 y^{2} - 48 x - 20 y - 76 = 0

What is 1-(3x^2+5x)/y =0 ?
The solution to 1-(3x^2+5x)/y =0 is Parabola with (h,k)=(-5/6 ,-25/12),p= 1/12