What is (x-9)^2+(y)^2=(x-6^2)+(y+3)^2 ?

The solution to (x-9)^2+(y)^2=(x-6^2)+(y+3)^2 is Parabola with (h,k)=(19/2 , 107/24),p= 3/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x-9)^2+(y)^2=(x-6^2)+(y+3)^2

(x - 9)^{2} + (y)^{2} = (x - 6^{2}) + (y + 3)^{2}

(h, k) = (\frac{19}{2}, \frac{107}{24}), p = \frac{3}{2}

Solution steps

(x - 9)^{2} + y^{2} = (x - 6^{2}) + (y + 3)^{2}

Rewrite

(x - 9)^{2} + y^{2} = (x - 6^{2}) + (y + 3)^{2}

in the standard form

4 \cdot \frac{3}{2} (y - \frac{107}{24}) = (x - \frac{19}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{19}{2}, \frac{107}{24}), p = \frac{3}{2}

x - y^{2} = 19

x - y^{2} = 13

y^{2} - 2 y - 4 x + 17 = 0

(x - \frac{1}{2})^{2} = 8 (y + 5)

x - y^{2} = 10

What is (x-9)^2+(y)^2=(x-6^2)+(y+3)^2 ?
The solution to (x-9)^2+(y)^2=(x-6^2)+(y+3)^2 is Parabola with (h,k)=(19/2 , 107/24),p= 3/2