(x-9)^2+(y)^2=(x-6^2)+(y+3)^2

解

(x - 9)^{2} + (y)^{2} = (x - 6^{2}) + (y + 3)^{2}

(h, k) = (\frac{19}{2}, \frac{107}{24}), p = \frac{3}{2}

解答ステップ

(x - 9)^{2} + y^{2} = (x - 6^{2}) + (y + 3)^{2}

(x - 9)^{2} + y^{2} = (x - 6^{2}) + (y + 3)^{2}

を標準的な形式で書き換える

4 \cdot \frac{3}{2} (y - \frac{107}{24}) = (x - \frac{19}{2})^{2}

ゆえに放物線の特性は:

(h, k) = (\frac{19}{2}, \frac{107}{24}), p = \frac{3}{2}