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Popular >

vertices 16x^2+y^2=16

Solution

vertices

16 x^{2} + y^{2} = 16

Solution

(0, 4), (0, - 4)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

16 x^{2} + y^{2} = 16 :

Ellipse with center

(h, k) = (0, 0), b = 4, a = 1

(0, 0 + 4), (0, 0 - 4)

Refine

(0, 4), (0, - 4)

Popular Examples

foci (y^2)/9-(x^2)/(16)=1 foci

\frac{y ^{2}}{9} - \frac{x ^{2}}{16} = 1

foci (x^2)/9+(y^2)/(16)=1 foci

\frac{x ^{2}}{9} + \frac{y ^{2}}{16} = 1

foci (x^2)/(36)-(y^2)/(64)=1 foci

\frac{x ^{2}}{36} - \frac{y ^{2}}{64} = 1

x^{2} = - 6 y

y^{2} - 4 y - 4 x = 0

Frequently Asked Questions (FAQ)

What is the vertices 16x^2+y^2=16 ?
The vertices 16x^2+y^2=16 is (0,4),(0,-4)