What is f(x)(3/4)^2=3x^2-x+5 ?

The solution to f(x)(3/4)^2=3x^2-x+5 is Parabola with (h,k)=(1/6 , 236/27),p= 3/64

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f(x)(3/4)^2=3x^2-x+5

f (x) (\frac{3}{4})^{2} = 3 x^{2} - x + 5

(h, k) = (\frac{1}{6}, \frac{236}{27}), p = \frac{3}{64}

Solution steps

y (\frac{3}{4})^{2} = 3 x^{2} - x + 5

Rewrite

y (\frac{3}{4})^{2} = 3 x^{2} - x + 5

in the standard form

4 \cdot \frac{3}{64} (y - \frac{236}{27}) = (x - \frac{1}{6})^{2}

Therefore parabola properties are:

(h, k) = (\frac{1}{6}, \frac{236}{27}), p = \frac{3}{64}

2 x^{2} + 2 x^{2} - 8 x - 12 y + 8 = 0

- y = x^{2} + 2

- y = x^{2} + 1

x^{2} + 4 x + 8 y - 28 = 0

y \geq 3 x^{2} - 9 x + 6

What is f(x)(3/4)^2=3x^2-x+5 ?
The solution to f(x)(3/4)^2=3x^2-x+5 is Parabola with (h,k)=(1/6 , 236/27),p= 3/64