What is the answer to (2x-10)+(2x-3)+(x-2)=50f(x,y)y ?

The answer to (2x-10)+(2x-3)+(x-2)=50f(x,y)y is x=10yf+3

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(2x-10)+(2x-3)+(x-2)=50f(x,y)y

solve for

x, (2 x - 10) + (2 x - 3) + (x - 2) = 50 f y

x = 10 y f + 3

Solution steps

(2 x - 10) + (2 x - 3) + (x - 2) = 50 f y

Remove parentheses:

(a) = a

2 x - 10 + 2 x - 3 + x - 2 = 50 f y

Group like terms

2 x + 2 x + x - 10 - 3 - 2 = 50 f y

Add similar elements:

2 x + 2 x + x = 5 x

5 x - 10 - 3 - 2 = 50 f y

Subtract the numbers:

- 10 - 3 - 2 = - 15

5 x - 15 = 50 f y

Move

15

to the right side

5 x = 50 f y + 15

Divide both sides by

5

x = 10 y f + 3

x - y^{2} = - 7

(x + 1)^{2} + (y + 6) = 19

x - y^{2} = - 5

4 x^{2} - 32 y = 0

2 x^{2} + 3 r (x) + 1 = 0

What is the answer to (2x-10)+(2x-3)+(x-2)=50f(x,y)y ?
The answer to (2x-10)+(2x-3)+(x-2)=50f(x,y)y is x=10yf+3