What is f(x)>0.6x-x^2+7 ?

The solution to f(x)>0.6x-x^2+7 is Parabola with (h,k)=(0.3,7.09),p=-1/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

f(x)>0.6x-x^2+7

f (x) > 0.6 x - x^{2} + 7

(h, k) = (0.3, 7.09), p = - \frac{1}{4}

Solution steps

y > 0.6 x - x^{2} + 7

Rewrite

y > 0.6 x - x^{2} + 7

in the standard form

4 (- \frac{1}{4}) (y - 7.09) = (x - 0.3)^{2}

Therefore parabola properties are:

(h, k) = (0.3, 7.09), p = - \frac{1}{4}

What is f(x)>0.6x-x^2+7 ?
The solution to f(x)>0.6x-x^2+7 is Parabola with (h,k)=(0.3,7.09),p=-1/4