What is 6(x-3^2)+6(y+7)^2=216 ?

The solution to 6(x-3^2)+6(y+7)^2=216 is Parabola with (h,k)=(45,-7),p=-1/4

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6(x-3^2)+6(y+7)^2=216

6 (x - 3^{2}) + 6 (y + 7)^{2} = 216

(h, k) = (45, - 7), p = - \frac{1}{4}

Solution steps

6 (x - 3^{2}) + 6 (y + 7)^{2} = 216

Rewrite

6 (x - 3^{2}) + 6 (y + 7)^{2} = 216

in the standard form:

4 (- \frac{1}{4}) (x - 45) = (y - (- 7))^{2}

Therefore parabola properties are:

(h, k) = (45, - 7), p = - \frac{1}{4}

(x + 5) (x - 5) = - Q (x)

x = (y + 2)^{2} - 3

\frac{1}{12} y^{2} - \frac{1}{2} y - \frac{13}{4} = x

x^{2} - 10 x - 64 y + 89 = 0

x^{2} + 12 x = - \frac{3}{2} y - 39

What is 6(x-3^2)+6(y+7)^2=216 ?
The solution to 6(x-3^2)+6(y+7)^2=216 is Parabola with (h,k)=(45,-7),p=-1/4