What is 5y^2-35x-40x-25=0 ?

The solution to 5y^2-35x-40x-25=0 is Parabola with (h,k)=(-1/3 ,0),p= 15/4

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5y^2-35x-40x-25=0

5 y^{2} - 35 x - 40 x - 25 = 0

(h, k) = (- \frac{1}{3}, 0), p = \frac{15}{4}

Solution steps

5 y^{2} - 35 x - 40 x - 25 = 0

Rewrite

5 y^{2} - 35 x - 40 x - 25 = 0

in the standard form:

4 \cdot \frac{15}{4} (x - (- \frac{1}{3})) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (- \frac{1}{3}, 0), p = \frac{15}{4}

y^{2} + 12 y - 5 x + 16 = 0

(x - 5)^{(2)} = - 8 (y - 3)

3 x^{2} - 8 y = 0

2 y - x^{2} + 2 = 0

y^{2} = - \frac{4}{5} (x - 2)

What is 5y^2-35x-40x-25=0 ?
The solution to 5y^2-35x-40x-25=0 is Parabola with (h,k)=(-1/3 ,0),p= 15/4