x^2+5y=9

Lösung

x^{2} + 5 y = 9

(h, k) = (0, \frac{9}{5}), p = - \frac{5}{4}

Schritte zur Lösung

x^{2} + 5 y = 9

Rewrite

x^{2} + 5 y = 9

in the standard form:

4 (- \frac{5}{4}) (y - \frac{9}{5}) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, \frac{9}{5}), p = - \frac{5}{4}

y^{2} + 20 x + 100 = 0

(4 p + 12)^{2} - 4 \cdot 2 (12 p + q + 12) > 0

\frac{x - 2}{2} = y^{2}

x^{2} + 5 y = 0

5 = y^{2} + x