x^2+4y+4x=0

Lösung

x^{2} + 4 y + 4 x = 0

(h, k) = (- 2, 1), p = - 1

Schritte zur Lösung

x^{2} + 4 y + 4 x = 0

Rewrite

x^{2} + 4 y + 4 x = 0

in the standard form

4 (- 1) (y - 1) = (x - (- 2))^{2}

Therefore parabola properties are:

(h, k) = (- 2, 1), p = - 1

(y - 1)^{2} - x = 3

2 y - 3 x^{2} + 3 = 0

y = 2 x^{2} + 8 x + 13

2 x^{2} - 8 \cdot (- 6) y + 10 = 0

(x - h)^{2} = 4 a y