yy+3x=2

Lösung

yy + 3 x = 2

(h, k) = (\frac{2}{3}, 0), p = - \frac{3}{4}

Schritte zur Lösung

yy + 3 x = 2

Rewrite

yy + 3 x = 2

in the standard form:

4 (- \frac{3}{4}) (x - \frac{2}{3}) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (\frac{2}{3}, 0), p = - \frac{3}{4}

x^{2} + 2 = 2 \cdot p (x)

x^{2} + y - 8 = 0

r (x) \leq x^{2} + 4 x + 6

x^{2} = \frac{18}{5} (y + 10)

6 y = x^{2} + \frac{1}{2}