What is 12x^2+10x-6y+1=0 ?

The solution to 12x^2+10x-6y+1=0 is Parabola with (h,k)=(-5/12 ,-13/72),p= 1/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

12x^2+10x-6y+1=0

12 x^{2} + 10 x - 6 y + 1 = 0

(h, k) = (- \frac{5}{12}, - \frac{13}{72}), p = \frac{1}{8}

Solution steps

12 x^{2} + 10 x - 6 y + 1 = 0

Rewrite

12 x^{2} + 10 x - 6 y + 1 = 0

in the standard form

4 \cdot \frac{1}{8} (y - (- \frac{13}{72})) = (x - (- \frac{5}{12}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{5}{12}, - \frac{13}{72}), p = \frac{1}{8}

y \geq 4 - x^{2}

y^{(2)} + 4 y + 8 x - 12 = 0

x = \frac{1}{4} (y + 4)^{2} + 2

(y - 6)^{2} = - \frac{3}{2} (x + 2)

3 f (x) = 2 x^{2} - 3 x

What is 12x^2+10x-6y+1=0 ?
The solution to 12x^2+10x-6y+1=0 is Parabola with (h,k)=(-5/12 ,-13/72),p= 1/8