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Beliebt Geometry >

c=z^2+14

Lösung

c = z^{2} + 14

Lösung

(h, k) = (14, 0), p = \frac{1}{4}

Schritte zur Lösung

c = z^{2} + 14

Rewrite

c = z^{2} + 14

in the standard form:

4 \cdot \frac{1}{4} (c - 14) = (z - 0)^{2}

Therefore parabola properties are:

(h, k) = (14, 0), p = \frac{1}{4}

Graph

Beliebte Beispiele

(y-1)^2=16(x+1)

x=e^{2((ln(y)))}

(y+3)^2=15(x-6)