What is (y-0.5)^2=2(x-2.5) ?

The solution to (y-0.5)^2=2(x-2.5) is Parabola with (h,k)=(5/2 ,0.5),p= 1/2

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(y-0.5)^2=2(x-2.5)

(y - 0.5)^{2} = 2 (x - 2.5)

(h, k) = (\frac{5}{2}, 0.5), p = \frac{1}{2}

Solution steps

(y - 0.5)^{2} = 2 (x - 2.5)

Rewrite

(y - 0.5)^{2} = 2 (x - 2.5)

in the standard form:

4 \cdot \frac{1}{2} (x - \frac{5}{2}) = (y - 0.5)^{2}

Therefore parabola properties are:

(h, k) = (\frac{5}{2}, 0.5), p = \frac{1}{2}

(x - 5)^{2} = 12 (y + 2)

4 x^{2} - \frac{1}{2} x^{2} + 8 x - 2 y = - 2

x = - 3 (y + 1)^{2} + 2

- \frac{1}{4} (x - 8) = (y + 5)^{2}

x^{2} = - 8 (y + 1)

What is (y-0.5)^2=2(x-2.5) ?
The solution to (y-0.5)^2=2(x-2.5) is Parabola with (h,k)=(5/2 ,0.5),p= 1/2