What is 10p(x)+x+0.01x^2=700 ?

The solution to 10p(x)+x+0.01x^2=700 is Parabola with (h,k)=(-50,72.5),p=-250

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10p(x)+x+0.01x^2=700

10 p (x) + x + 0.01 x^{2} = 700

(h, k) = (- 50, 72.5), p = - 250

Solution steps

10 y + x + 0.01 x^{2} = 700

Rewrite

10 y + x + 0.01 x^{2} = 700

in the standard form

4 (- 250) (y - 72.5) = (x - (- 50))^{2}

Therefore parabola properties are:

(h, k) = (- 50, 72.5), p = - 250

y + 1 = (x + 1)^{2}

a 6 a - 8 b + 26 = 0

x^{2} + y \leq 9

4 y^{2} + 8 y + 16 - x = 0

2 y^{2} - 9 x = 0

What is 10p(x)+x+0.01x^2=700 ?
The solution to 10p(x)+x+0.01x^2=700 is Parabola with (h,k)=(-50,72.5),p=-250