4x(x-2)+5y-4=0

Lösung

4 x (x - 2) + 5 y - 4 = 0

(h, k) = (1, \frac{8}{5}), p = - \frac{5}{16}

Schritte zur Lösung

4 x (x - 2) + 5 y - 4 = 0

Rewrite

4 x (x - 2) + 5 y - 4 = 0

in the standard form

4 (- \frac{5}{16}) (y - \frac{8}{5}) = (x - 1)^{2}

Therefore parabola properties are:

(h, k) = (1, \frac{8}{5}), p = - \frac{5}{16}

1 x^{2} - 2 y - 15 = 0

x = 2 (y - 4)^{2} + 1

y = x^{2} + 11 x - 2

F = m \frac{v ^{2}}{r}

- y^{2} = x + 16