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Popular >

foci x=-2y^2

Solution

foci

x = - 2 y^{2}

Solution

(- \frac{1}{8}, 0)

Solution steps

Rewrite

x = - 2 y^{2}

in the standard form:

4 (- \frac{1}{8}) (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = - \frac{1}{8}

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(0, 0)

along the x-axis

(0 + p, 0)

= (0 + (- \frac{1}{8}), 0)

Refine

(- \frac{1}{8}, 0)

Popular Examples

x^{2} = 20 y

3x^2+y^2+18x-2y-8=0

3 x^{2} + y^{2} + 18 x - 2 y - 8 = 0

eccentricity (x^2)/5+(y^2)/9 =1 eccentricity

\frac{x ^{2}}{5} + \frac{y ^{2}}{9} = 1

vertices 3x^2+2y^2=6 vertices

3 x^{2} + 2 y^{2} = 6

foci (x^2)/(25)+(y^2)/(25)=1 foci

\frac{x ^{2}}{25} + \frac{y ^{2}}{25} = 1

Frequently Asked Questions (FAQ)

What is the foci x=-2y^2 ?
The foci x=-2y^2 is (-1/8 ,0)