What is 2x^{(2)}+2y+2x-y=0 ?

The solution to 2x^{(2)}+2y+2x-y=0 is Parabola with (h,k)=(-1/2 , 1/2),p=-1/8

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2x^{(2)}+2y+2x-y=0

2 x^{(2)} + 2 y + 2 x - y = 0

(h, k) = (- \frac{1}{2}, \frac{1}{2}), p = - \frac{1}{8}

Solution steps

2 x^{2} + 2 y + 2 x - y = 0

Rewrite

2 x^{2} + 2 y + 2 x - y = 0

in the standard form

4 (- \frac{1}{8}) (y - \frac{1}{2}) = (x - (- \frac{1}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{1}{2}, \frac{1}{2}), p = - \frac{1}{8}

9 x^{2} + 6 x - 2 y = 0

f (x) = - 2 x^{2} - 8 x - 11

y^{2} + x \geq 0

4 x^{2} - 8 x + 3 m (x) = 5

v^{2} = y^{2} + 2 a x

What is 2x^{(2)}+2y+2x-y=0 ?
The solution to 2x^{(2)}+2y+2x-y=0 is Parabola with (h,k)=(-1/2 , 1/2),p=-1/8