What is (x-5)^2-2(y+2)=0 ?

The solution to (x-5)^2-2(y+2)=0 is Parabola with (h,k)=(5,-2),p= 1/2

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(x-5)^2-2(y+2)=0

(x - 5)^{2} - 2 (y + 2) = 0

(h, k) = (5, - 2), p = \frac{1}{2}

Solution steps

(x - 5)^{2} - 2 (y + 2) = 0

Rewrite

(x - 5)^{2} - 2 (y + 2) = 0

in the standard form:

4 \cdot \frac{1}{2} (y - (- 2)) = (x - 5)^{2}

Therefore parabola properties are:

(h, k) = (5, - 2), p = \frac{1}{2}

What is (x-5)^2-2(y+2)=0 ?
The solution to (x-5)^2-2(y+2)=0 is Parabola with (h,k)=(5,-2),p= 1/2