What is y^2-8y+16=x^2-6x+y^2-4y+13 ?

The solution to y^2-8y+16=x^2-6x+y^2-4y+13 is Parabola with (h,k)=(3,3),p=-1

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y^2-8y+16=x^2-6x+y^2-4y+13

y^{2} - 8 y + 16 = x^{2} - 6 x + y^{2} - 4 y + 13

(h, k) = (3, 3), p = - 1

Solution steps

y^{2} - 8 y + 16 = x^{2} - 6 x + y^{2} - 4 y + 13

Rewrite

y^{2} - 8 y + 16 - x^{2} + 6 x - y^{2} + 4 y - 13 = 0

in the standard form

4 (- 1) (y - 3) = (x - 3)^{2}

Therefore parabola properties are:

(h, k) = (3, 3), p = - 1

x^{2} + 4 x - 8 y + 28 = 0

(y - 2)^{2} = - 4 x

(10 + y) 2 - y^{2} = - 3 x + 12

(y - 3)^{2} = - 20 (x + 2)

3 a - 5 (b - a) = (a - b) \cdot (a + b) - a (a - 1)

What is y^2-8y+16=x^2-6x+y^2-4y+13 ?
The solution to y^2-8y+16=x^2-6x+y^2-4y+13 is Parabola with (h,k)=(3,3),p=-1