What is x^2-sqrt(2/3)y-3=sqrt(8/27)y-3 ?

The solution to x^2-sqrt(2/3)y-3=sqrt(8/27)y-3 is Parabola with (h,k)=(0,0),p= 5/(6sqrt(6))

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x^2-sqrt(2/3)y-3=sqrt(8/27)y-3

x^{2} - \frac{2}{3} y - 3 = \frac{8}{27} y - 3

(h, k) = (0, 0), p = \frac{5}{6 6}

Solution steps

x^{2} - \frac{2}{3} y - 3 = \frac{8}{27} y - 3

Rewrite

x^{2} - \frac{2}{3} y - 3 = \frac{8}{27} y - 3

in the standard form:

4 \cdot \frac{5}{6 6} (y - 0) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = \frac{5}{6 6}

x + (- 7) y^{2} = 0

x^{2} - 8 x - 8 y - 8 = 0

(x + 2)^{2} = 4 (y - 2)

x = - 50 (y^{2} - 24 y + 80)

x^{2} - 8 x - 24 y + 64 = 0

What is x^2-sqrt(2/3)y-3=sqrt(8/27)y-3 ?
The solution to x^2-sqrt(2/3)y-3=sqrt(8/27)y-3 is Parabola with (h,k)=(0,0),p= 5/(6sqrt(6))