What is (f(x))/(100)=-6.25x^2-12.5x+50 ?

The solution to (f(x))/(100)=-6.25x^2-12.5x+50 is Parabola with (h,k)=(-1,5625),p=-1/2500

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(f(x))/(100)=-6.25x^2-12.5x+50

\frac{f ( x )}{100} = - 6.25 x^{2} - 12.5 x + 50

(h, k) = (- 1, 5625), p = - \frac{1}{2500}

Solution steps

\frac{y}{100} = - 6.25 x^{2} - 12.5 x + 50

Rewrite

\frac{y}{100} = - 6.25 x^{2} - 12.5 x + 50

in the standard form

4 (- \frac{1}{2500}) (y - 5625) = (x - (- 1))^{2}

Therefore parabola properties are:

(h, k) = (- 1, 5625), p = - \frac{1}{2500}

(x - 5)^{2} = - 8 (y - 2)

x^{2} + 4 x + 20 y - 56 = 0

x = y^{(2)}

2 x^{2} + 3 x + 1 - p (x) = 0

- y = (x - 8)^{2} - 5

What is (f(x))/(100)=-6.25x^2-12.5x+50 ?
The solution to (f(x))/(100)=-6.25x^2-12.5x+50 is Parabola with (h,k)=(-1,5625),p=-1/2500