What is x^2+y^2+4x-6y-3=0 ?

The solution to x^2+y^2+4x-6y-3=0 is Circle with (a,b)=(-2,3),r=4

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x^2+y^2+4x-6y-3=0

x^{2} + y^{2} + 4 x - 6 y - 3 = 0

(a, b) = (- 2, 3), r = 4

Solution steps

x^{2} + y^{2} + 4 x - 6 y - 3 = 0

Rewrite

x^{2} + y^{2} + 4 x - 6 y - 3 = 0

in the form of the standard circle equation

(x - (- 2))^{2} + (y - 3)^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (- 2, 3), r = 4

\frac{x ^{2}}{25} - \frac{y ^{2}}{4} = 1

9 x^{2} + 16 y^{2} = 144

y^{2} = - 25 x

\frac{x ^{2}}{4} - \frac{y ^{2}}{9} = 1

\frac{x ^{2}}{25} + \frac{y ^{2}}{4} = 1

What is x^2+y^2+4x-6y-3=0 ?
The solution to x^2+y^2+4x-6y-3=0 is Circle with (a,b)=(-2,3),r=4