x^2-3x-y+2=0

Lösung

x^{2} - 3 x - y + 2 = 0

(h, k) = (\frac{3}{2}, - \frac{1}{4}), p = \frac{1}{4}

Schritte zur Lösung

x^{2} - 3 x - y + 2 = 0

Rewrite

x^{2} - 3 x - y + 2 = 0

in the standard form

4 \cdot \frac{1}{4} (y - (- \frac{1}{4})) = (x - \frac{3}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{3}{2}, - \frac{1}{4}), p = \frac{1}{4}

(x + 1) 2 + y^{2} = 4

(x - h)^{2} = 4 a (y - k)

y \geq x^{2} + 3

- y^{2} + x - 4 = 0

y \geq x^{2} - 6