What is y^2+y+x-20=0.2y^2-x-3y-4 ?

The solution to y^2+y+x-20=0.2y^2-x-3y-4 is Parabola with (h,k)=(10.5,-2.5),p=-0.625

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y^2+y+x-20=0.2y^2-x-3y-4

y^{2} + y + x - 20 = 0.2 y^{2} - x - 3 y - 4

(h, k) = (10.5, - 2.5), p = - 0.625

Solution steps

y^{2} + y + x - 20 = 0.2 y^{2} - x - 3 y - 4

Rewrite

y^{2} + y + x - 20 = 0.2 y^{2} - x - 3 y - 4

in the standard form

4 (- 0.625) (x - 10.5) = (y - (- 2.5))^{2}

Therefore parabola properties are:

(h, k) = (10.5, - 2.5), p = - 0.625

x^{2} + 6 x + 16 y - 7 = 0

2 x^{2} + 8 y - 12 = 0

- 5 x^{2} + 7 y - 11 = 0

x (2 x - 5) = z

x^{2} + 12 y + 12 = 0

What is y^2+y+x-20=0.2y^2-x-3y-4 ?
The solution to y^2+y+x-20=0.2y^2-x-3y-4 is Parabola with (h,k)=(10.5,-2.5),p=-0.625