What is (x+5/4)^2=(h(x))/(16) ?

The solution to (x+5/4)^2=(h(x))/(16) is Parabola with (h,k)=(-5/4 ,0),p= 1/64

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(x+5/4)^2=(h(x))/(16)

(x + \frac{5}{4})^{2} = \frac{h ( x )}{16}

(h, k) = (- \frac{5}{4}, 0), p = \frac{1}{64}

Solution steps

(x + \frac{5}{4})^{2} = \frac{y}{16}

Rewrite

(x + \frac{5}{4})^{2} = \frac{y}{16}

in the standard form:

4 \cdot \frac{1}{64} (y - 0) = (x - (- \frac{5}{4}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{5}{4}, 0), p = \frac{1}{64}

x^{2} - 2 y = 30

y^{2} - 8 x - 16 y - 24 = 0

(x + 2)^{2} = - 2 (4 + y)

(x + 1)^{2} = - 12 (y - 2)

(y - 5)^{2} = 40 x

What is (x+5/4)^2=(h(x))/(16) ?
The solution to (x+5/4)^2=(h(x))/(16) is Parabola with (h,k)=(-5/4 ,0),p= 1/64