What is the d/(dX)((X^2)/2+2X-3) ?

The d/(dX)((X^2)/2+2X-3) is X+2

What is the first d/(dX)((X^2)/2+2X-3) ?

The first d/(dX)((X^2)/2+2X-3) is X+2

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\frac{d}{d X} (\frac{X ^{2}}{2} + 2 X - 3)

X + 2

Solution steps

\frac{d}{d X} (\frac{X ^{2}}{2} + 2 X - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d X} (\frac{X ^{2}}{2}) + \frac{d}{d X} (2 X) - \frac{d}{d X} (3)

\frac{d}{d X} (\frac{X ^{2}}{2}) = X

\frac{d}{d X} (2 X) = 2

\frac{d}{d X} (3) = 0

= X + 2 - 0

Simplify

= X + 2

x^{2} + 4 m (x) + 4 = 0

- (x - 2)^{2} = - 2 y - 4

(y - 5)^{2} = 3 (x + 3)

- y^{2} + x + 6 y = 8

x^{2} - k (x) + 10 = 0