What is (x-31/4)^2+(y+7/4)= 81/4 ?

The solution to (x-31/4)^2+(y+7/4)= 81/4 is Parabola with (h,k)=(31/4 , 37/2),p=-1/4

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(x-31/4)^2+(y+7/4)= 81/4

(x - \frac{31}{4})^{2} + (y + \frac{7}{4}) = \frac{81}{4}

(h, k) = (\frac{31}{4}, \frac{37}{2}), p = - \frac{1}{4}

Solution steps

(x - \frac{31}{4})^{2} + (y + \frac{7}{4}) = \frac{81}{4}

Rewrite

(x - \frac{31}{4})^{2} + (y + \frac{7}{4}) = \frac{81}{4}

in the standard form:

4 (- \frac{1}{4}) (y - \frac{37}{2}) = (x - \frac{31}{4})^{2}

Therefore parabola properties are:

(h, k) = (\frac{31}{4}, \frac{37}{2}), p = - \frac{1}{4}

y = - \frac{1}{4} (x + 9)^{2} - 7

(x - 0)^{2} = 16 (y - 0)

x = y^{2} - 6 y + 10

x^{2} + 2 y + 2 = 0

y > (x + 2)^{2} - 4

What is (x-31/4)^2+(y+7/4)= 81/4 ?
The solution to (x-31/4)^2+(y+7/4)= 81/4 is Parabola with (h,k)=(31/4 , 37/2),p=-1/4