What is 2x+y-10=y^2-8x-4 ?

The solution to 2x+y-10=y^2-8x-4 is Parabola with (h,k)=(23/40 , 1/2),p= 5/2

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2x+y-10=y^2-8x-4

2 x + y - 10 = y^{2} - 8 x - 4

(h, k) = (\frac{23}{40}, \frac{1}{2}), p = \frac{5}{2}

Solution steps

2 x + y - 10 = y^{2} - 8 x - 4

Rewrite

2 x + y - 10 = y^{2} - 8 x - 4

in the standard form

4 \cdot \frac{5}{2} (x - \frac{23}{40}) = (y - \frac{1}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{23}{40}, \frac{1}{2}), p = \frac{5}{2}

x = - 3 (y + 2)^{2} + 1

(x - 4)^{2} = 8 (y + 2)

a^{2} + b = 0

y^{2} = - 2 (x - 9)

3 y^{(2)} - 24 y - 24 x + 96 = 0

What is 2x+y-10=y^2-8x-4 ?
The solution to 2x+y-10=y^2-8x-4 is Parabola with (h,k)=(23/40 , 1/2),p= 5/2