What is the foci (x^2)/9+(y^2)/4 =1 ?

The foci (x^2)/9+(y^2)/4 =1 is (sqrt(5),0),(-sqrt(5),0)

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foci (x^2)/9+(y^2)/4 =1

foci

\frac{x ^{2}}{9} + \frac{y ^{2}}{4} = 1

(5, 0), (- 5, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{x ^{2}}{9} + \frac{y ^{2}}{4} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 3, b = 2

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 3^{2} - 2^{2} : 5

(0 + 5, 0), (0 - 5, 0)

Refine

(5, 0), (- 5, 0)

f (x) = - 2 x^{2}

x^{2} + 2 y^{2} = 4

x^{2} + 4 y^{2} = 4

x^{2} + 4 x + y^{2} - 6 y = - 4

x^{2} + x + 1

What is the foci (x^2)/9+(y^2)/4 =1 ?
The foci (x^2)/9+(y^2)/4 =1 is (sqrt(5),0),(-sqrt(5),0)