What is 18y^2-24y+36x-1=0 ?

The solution to 18y^2-24y+36x-1=0 is Parabola with (h,k)=(1/4 , 2/3),p=-1/2

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18y^2-24y+36x-1=0

18 y^{2} - 24 y + 36 x - 1 = 0

(h, k) = (\frac{1}{4}, \frac{2}{3}), p = - \frac{1}{2}

Solution steps

18 y^{2} - 24 y + 36 x - 1 = 0

Rewrite

18 y^{2} - 24 y + 36 x - 1 = 0

in the standard form

4 (- \frac{1}{2}) (x - \frac{1}{4}) = (y - \frac{2}{3})^{2}

Therefore parabola properties are:

(h, k) = (\frac{1}{4}, \frac{2}{3}), p = - \frac{1}{2}

3 x^{2} - 2 x + k (x) = 0

(y + 2)^{2} = - 12 (x - 3)

28 (x - 5) = (y + 1)^{2}

(x - 0)^{2} = 4 (5) (y - 0)

y + 1 - 6 x^{2} = 0

What is 18y^2-24y+36x-1=0 ?
The solution to 18y^2-24y+36x-1=0 is Parabola with (h,k)=(1/4 , 2/3),p=-1/2