What is 3y^2-8x+5y-13=0 ?

The solution to 3y^2-8x+5y-13=0 is Parabola with (h,k)=(-181/96 ,-5/6),p= 2/3

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3y^2-8x+5y-13=0

3 y^{2} - 8 x + 5 y - 13 = 0

(h, k) = (- \frac{181}{96}, - \frac{5}{6}), p = \frac{2}{3}

Solution steps

3 y^{2} - 8 x + 5 y - 13 = 0

Rewrite

3 y^{2} - 8 x + 5 y - 13 = 0

in the standard form

4 \cdot \frac{2}{3} (x - (- \frac{181}{96})) = (y - (- \frac{5}{6}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{181}{96}, - \frac{5}{6}), p = \frac{2}{3}

y^{(2)} = \frac{( 18 - 3 x )}{( 2 )}

\frac{1}{3} π r^{2} h = v

f (x) - 5 = x^{2} - 3 x + 2

x^{2} - 8 x + 4 y + 20 = 0

(x + 3)^{2} = 24 (y - 2)

What is 3y^2-8x+5y-13=0 ?
The solution to 3y^2-8x+5y-13=0 is Parabola with (h,k)=(-181/96 ,-5/6),p= 2/3