What is (x-3)^2-1f(x)=-2x^2+8x+5 ?

The solution to (x-3)^2-1f(x)=-2x^2+8x+5 is Parabola with (h,k)=(7/3 ,-37/3),p= 1/12

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(x-3)^2-1f(x)=-2x^2+8x+5

(x - 3)^{2} - 1 f (x) = - 2 x^{2} + 8 x + 5

(h, k) = (\frac{7}{3}, - \frac{37}{3}), p = \frac{1}{12}

Solution steps

(x - 3)^{2} - 1 \cdot y = - 2 x^{2} + 8 x + 5

Rewrite

(x - 3)^{2} - 1 \cdot y = - 2 x^{2} + 8 x + 5

in the standard form

4 \cdot \frac{1}{12} (y - (- \frac{37}{3})) = (x - \frac{7}{3})^{2}

Therefore parabola properties are:

(h, k) = (\frac{7}{3}, - \frac{37}{3}), p = \frac{1}{12}

y^{2} + 8 y + 6 x + 16 = 0

2 x^{2} - 20 x - 2 m (x) > 0

y - 3 = x^{2} - 4 x

y^{2} - \frac{1}{5} x + 2 y = - \frac{19}{5}

x = (h (x) + 1)^{2}

What is (x-3)^2-1f(x)=-2x^2+8x+5 ?
The solution to (x-3)^2-1f(x)=-2x^2+8x+5 is Parabola with (h,k)=(7/3 ,-37/3),p= 1/12