What is (x-5/2)^2=7(y+3.75) ?

The solution to (x-5/2)^2=7(y+3.75) is Parabola with (h,k)=(5/2 ,-3.75),p= 7/4

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(x-5/2)^2=7(y+3.75)

(x - \frac{5}{2})^{2} = 7 (y + 3.75)

(h, k) = (\frac{5}{2}, - 3.75), p = \frac{7}{4}

Solution steps

(x - \frac{5}{2})^{2} = 7 (y + 3.75)

Rewrite

(x - \frac{5}{2})^{2} = 7 (y + 3.75)

in the standard form:

4 \cdot \frac{7}{4} (y - (- 3.75)) = (x - \frac{5}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{5}{2}, - 3.75), p = \frac{7}{4}

x = \frac{- 3 \cdot y ^{2}}{4}

x^{2} + 2 x + 2 y + 7 = 0

2 f (x) = 2 x^{2} + 5

x^{2} - 2 x + 4 y - 7 = 0

(x - h)^{2} = 4 (- 8) (y - 3)

What is (x-5/2)^2=7(y+3.75) ?
The solution to (x-5/2)^2=7(y+3.75) is Parabola with (h,k)=(5/2 ,-3.75),p= 7/4