What is (a-1)/b =(a+1)/b+(b-1)/a ?

The solution to (a-1)/b =(a+1)/b+(b-1)/a is Parabola with (h,k)=(1/8 , 1/2),p=-1/2

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(a-1)/b =(a+1)/b+(b-1)/a

\frac{a - 1}{b} = \frac{a + 1}{b} + \frac{b - 1}{a}

(h, k) = (\frac{1}{8}, \frac{1}{2}), p = - \frac{1}{2}

Solution steps

\frac{a - 1}{b} = \frac{a + 1}{b} + \frac{b - 1}{a}

Rewrite

\frac{a - 1}{b} - \frac{a + 1}{b} - \frac{b - 1}{a} = 0

in the standard form

4 (- \frac{1}{2}) (a - \frac{1}{8}) = (b - \frac{1}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{1}{8}, \frac{1}{2}), p = - \frac{1}{2}

x = (y + 3)^{2} - 7

y^{2} = \frac{x}{4}

y - x^{2} + 5 = 0

x^{2} = 4 (y + 1)

- x^{2} - 3 x + y = 0

What is (a-1)/b =(a+1)/b+(b-1)/a ?
The solution to (a-1)/b =(a+1)/b+(b-1)/a is Parabola with (h,k)=(1/8 , 1/2),p=-1/2