What is 2x^2-6x+5=2k(x)+k(x) ?

The solution to 2x^2-6x+5=2k(x)+k(x) is Parabola with (h,k)=(3/2 , 1/6),p= 3/8

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2x^2-6x+5=2k(x)+k(x)

2 x^{2} - 6 x + 5 = 2 k (x) + k (x)

(h, k) = (\frac{3}{2}, \frac{1}{6}), p = \frac{3}{8}

Solution steps

2 x^{2} - 6 x + 5 = 2 y + y

Rewrite

2 x^{2} - 6 x + 5 = 2 y + y

in the standard form

4 \cdot \frac{3}{8} (y - \frac{1}{6}) = (x - \frac{3}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{3}{2}, \frac{1}{6}), p = \frac{3}{8}

y = \frac{7}{4} x^{2}

2 x^{2} - x + 4 m (x) = 0

y = 6 x - 3 x^{2}

2 x^{2} + 8 y = 15

c \frac{c}{a} = \frac{- 1}{2}

What is 2x^2-6x+5=2k(x)+k(x) ?
The solution to 2x^2-6x+5=2k(x)+k(x) is Parabola with (h,k)=(3/2 , 1/6),p= 3/8