What is 2y^2+10x-3y+24=0 ?

The solution to 2y^2+10x-3y+24=0 is Parabola with (h,k)=(-183/80 , 3/4),p=-5/4

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2y^2+10x-3y+24=0

2 y^{2} + 10 x - 3 y + 24 = 0

(h, k) = (- \frac{183}{80}, \frac{3}{4}), p = - \frac{5}{4}

Solution steps

2 y^{2} + 10 x - 3 y + 24 = 0

Rewrite

2 y^{2} + 10 x - 3 y + 24 = 0

in the standard form

4 (- \frac{5}{4}) (x - (- \frac{183}{80})) = (y - \frac{3}{4})^{2}

Therefore parabola properties are:

(h, k) = (- \frac{183}{80}, \frac{3}{4}), p = - \frac{5}{4}

4 x^{2} - 12 y - 9 = 0

y^{2} = \frac{- 2 + 2 x}{3}

x^{2} - 8 x + q (x) = 0

y^{2} + 4 y + 4 = x

x^{2} + x + 6 k (x) > 0

What is 2y^2+10x-3y+24=0 ?
The solution to 2y^2+10x-3y+24=0 is Parabola with (h,k)=(-183/80 , 3/4),p=-5/4