What is ((y+1))/((x^2+y-2))=-2 ?

The solution to ((y+1))/((x^2+y-2))=-2 is Parabola with (h,k)=(0,1),p=-3/8

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((y+1))/((x^2+y-2))=-2

\frac{( y + 1 )}{( x ^{2} + y - 2 )} = - 2

(h, k) = (0, 1), p = - \frac{3}{8}

Solution steps

\frac{y + 1}{x ^{2} + y - 2} = - 2

Rewrite

\frac{y + 1}{x ^{2} + y - 2} + 2 = 0

in the standard form

4 (- \frac{3}{8}) (y - 1) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 1), p = - \frac{3}{8}

(x - 3)^{2} = - 3 (y - 2)

2 x = \frac{y ^{2}}{2}

y^{2} - 2 x + 2 y - 1 = 0

4 Y = - 3 (X - 2)^{2} - 5

x + 4 - y^{2} \geq 0

What is ((y+1))/((x^2+y-2))=-2 ?
The solution to ((y+1))/((x^2+y-2))=-2 is Parabola with (h,k)=(0,1),p=-3/8