What is the foci x^2-y^2=4 ?

The foci x^2-y^2=4 is (2sqrt(2),0),(-2sqrt(2),0)

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foci x^2-y^2=4

foci

x^{2} - y^{2} = 4

(22, 0), (- 22, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

x^{2} - y^{2} = 4 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 2, b = 2

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 2^{2} + 2^{2} : 22

(0 + 22, 0), (0 - 22, 0)

Refine

(22, 0), (- 22, 0)

y^{2} + 6 y - 2 x + 13 = 0

\frac{x ^{2}}{49} + \frac{y ^{2}}{16} = 1

f (x) = x^{2} + 2 x - 8

\frac{x ^{2}}{36} - \frac{y ^{2}}{9} = 1

y = x^{2}