What is 12x^2+3x-10y-1=0 ?

The solution to 12x^2+3x-10y-1=0 is Parabola with (h,k)=(-1/8 ,-19/160),p= 5/24

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12x^2+3x-10y-1=0

12 x^{2} + 3 x - 10 y - 1 = 0

(h, k) = (- \frac{1}{8}, - \frac{19}{160}), p = \frac{5}{24}

Solution steps

12 x^{2} + 3 x - 10 y - 1 = 0

Rewrite

12 x^{2} + 3 x - 10 y - 1 = 0

in the standard form

4 \cdot \frac{5}{24} (y - (- \frac{19}{160})) = (x - (- \frac{1}{8}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{1}{8}, - \frac{19}{160}), p = \frac{5}{24}

y^{2} - 6 y - 8 x - 7 = 0

x^{2} + 2 x - 20 y + 41 = 0

f (x) = x^{2} - 2 x - 6 f (2) - f (t)

2 x + 3 y^{2} = 7

x^{2} = 5 x - 3 k (x) + 3

What is 12x^2+3x-10y-1=0 ?
The solution to 12x^2+3x-10y-1=0 is Parabola with (h,k)=(-1/8 ,-19/160),p= 5/24