What is (x-3)^2=20(y+119/20) ?

The solution to (x-3)^2=20(y+119/20) is Parabola with (h,k)=(3,-119/20),p=5

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(x-3)^2=20(y+119/20)

(x - 3)^{2} = 20 (y + \frac{119}{20})

(h, k) = (3, - \frac{119}{20}), p = 5

Solution steps

(x - 3)^{2} = 20 (y + \frac{119}{20})

Rewrite

(x - 3)^{2} = 20 (y + \frac{119}{20})

in the standard form:

4 \cdot 5 (y - (- \frac{119}{20})) = (x - 3)^{2}

Therefore parabola properties are:

(h, k) = (3, - \frac{119}{20}), p = 5

(x - 1)^{2} = 2 y

y - (4 x)^{2} = 0

5 x^{2} + 3 y = 41

x = - 5 y - y^{2}

0 = x - y^{2}

What is (x-3)^2=20(y+119/20) ?
The solution to (x-3)^2=20(y+119/20) is Parabola with (h,k)=(3,-119/20),p=5